[Python] 프로그래머스 Lv0 : 물 부족

2025. 3. 1. 20:11


def solution(storage, usage, change):
	total_usage = 0
    
    for i in range(len(change)):
    	usage = usage * (change[i]+100)/100
        total_usage += usage
        if total_usage > storage:
        	return i
            
    return -1

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